Integrand size = 21, antiderivative size = 21 \[ \int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx=\text {Int}\left (\frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )},x\right ) \]
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Not integrable
Time = 0.00 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx=\int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx \\ \end{align*}
Not integrable
Time = 0.01 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.10 \[ \int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx=\int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx \]
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Not integrable
Time = 1.01 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00
\[\int \frac {1}{A +B \ln \left (\frac {e \left (b x +a \right )}{d x +c}\right )}d x\]
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Not integrable
Time = 0.28 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.19 \[ \int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx=\int { \frac {1}{B \log \left (\frac {{\left (b x + a\right )} e}{d x + c}\right ) + A} \,d x } \]
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Not integrable
Time = 0.85 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.90 \[ \int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx=\int \frac {1}{A + B \log {\left (\frac {e \left (a + b x\right )}{c + d x} \right )}}\, dx \]
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Not integrable
Time = 0.21 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.10 \[ \int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx=\int { \frac {1}{B \log \left (\frac {{\left (b x + a\right )} e}{d x + c}\right ) + A} \,d x } \]
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Not integrable
Time = 11.53 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.10 \[ \int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx=\int { \frac {1}{B \log \left (\frac {{\left (b x + a\right )} e}{d x + c}\right ) + A} \,d x } \]
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Not integrable
Time = 0.99 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.10 \[ \int \frac {1}{A+B \log \left (\frac {e (a+b x)}{c+d x}\right )} \, dx=\int \frac {1}{A+B\,\ln \left (\frac {e\,\left (a+b\,x\right )}{c+d\,x}\right )} \,d x \]
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